Adjusting Vout

Discussion in 'Homework Help' started by tech1, Dec 14, 2012.

  1. tech1

    Thread Starter New Member

    Oct 22, 2012
    I started studying electronics quite recently and I am trying to make an analog electronic circuit that will generate the Voltage output described below. I have attached a graph depicting the relation between a random Vin (black curve) and Vout (green curve). Both a and b are positive integers less than Vss, with b>a. Vin is a continuous signal.

    For Vin>b , Vout = Vss (e.g. +12 V)
    For a<Vin<b , Vout = 0 if Vin rose from a, or Vout = +Vss if it declined from b.
    For -a<Vin<a , Vout = 0
    For -b<Vin<-a, Vout = 0 if Vin declined from -a and Vout = -Vss if Vout rose from -b.
    For Vin<-b , Vout = -Vss

    Thanks in advance for any help
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  2. ScottWang


    Aug 23, 2012
    You can use LM339.
    1. Set the input reference voltage for two comparators, Vref as 2V,4V
    2. Two another input pins of the comparators connecting together and to be the input pin for Input signal.
    3. Two output connecting together, and pull a 10K resistor to the +12V, if you use +12V to be the Power.
    4. Do the same thing as positive side for the input signal of the negtive side.
    Last edited: Dec 15, 2012
  3. WBahn


    Mar 31, 2012
    Since this is homework, please show your efforts at a solution and we will go from there. Hint, think in terms of two Schmitt trigger comparators.