# AD633 Analog Multiplier Problem

Discussion in 'General Electronics Chat' started by syee10, Mar 18, 2011.

1. ### syee10 Thread Starter Member

Mar 26, 2010
59
0
Hi,

I have a problem here everyone. This is really make me going to crazy. I have an exact connection just like the connection in Figure 11.
Suppose i have a 3V input to the X1 and 3V input to the Y1. X2 and Y2 is grounded. Z is also grounded. In this case i should get a 0.9V because 3X3/10 it will be 0.9V. I am sure my there is no wrong in my connection because i had check through it many times. The answer i get from the output W is around 12.2V. What happen to my circuit actually? Is my AD633 IC spoil or broken and give me this result? Please assist me =(

You can find the AD633 Analog Multiplier Datasheet at http://www.analog.com/static/imported-files/data_sheets/AD633.pdf

2. ### Ron H AAC Fanatic!

Apr 14, 2005
7,050
657
Have you checked the voltage on every pin (and I mean all 8 of them), right at the point where the pin enters the body of the IC? If you have, then your IC is probably bad.

3. ### syee10 Thread Starter Member

Mar 26, 2010
59
0
How to confirm the IC is spoil or broken? Do you have any methods to check?

4. ### eblc1388 Senior Member

Nov 28, 2008
1,542
102
Ron just told you exactly how to check for that.

5. ### syee10 Thread Starter Member

Mar 26, 2010
59
0
Ok now i found what is the problem already. This is funny problem and i really dun know why this happen. Forget about what i post in the previous post, regardless which type of square wave i put into my input X1 and Y1. Square wave with positive peak and negative peak or square wave with positive peak and 0 is working fine with the AD633.
The funny thing is, when i connect a probe (connect to oscilloscope) to either my input X1 or Y1, the output is working fine! And when i disconnect the probe again from my input X1 or Y1, the output is always show me 12.3V!! Why is this happen? Why must i connect a probe to either X1 or Y1 in order to get a correct output?! Please comment..

6. ### beenthere Retired Moderator

Apr 20, 2004
15,815
283
What does the circuit look like (schematic)?

Nov 20, 2008
639
110

8. ### syee10 Thread Starter Member

Mar 26, 2010
59
0
The circuit is exactly same as the Figure 11 in the datasheet. The input to X1 and Y1 is a square waveform of 50Hz positive 1-5 high level voltage and 0 low voltage. What's wrong with the connection? Is the connection in Figure 11 in the datasheet miss out some components? Why must i connect a probe at either X1 or Y1 in order to get me a correct output?!

9. ### Ron H AAC Fanatic!

Apr 14, 2005
7,050
657
It may be due to oscillation. Do you have good power supply decoupling capacitors (typically 100nF) connected with short leads from pins 3 and 6 to ground?

10. ### syee10 Thread Starter Member

Mar 26, 2010
59
0
Yes i have connected the capacitor 0.1uF to the ground at pins 3 and 6. What you mean due to 'oscillation'?

11. ### Ron H AAC Fanatic!

Apr 14, 2005
7,050
657
Many analog circuits will oscillate if they do not have low power supply impedances. The capacitors provide this. See this article for more information.
http://electronicdesign.com/article...ign-techniques-solve-high-speed-op-amp-s.aspx

If you don't know what oscillation is, you are an electronics beginner, and analog multipliers will probably be a challenge for you.

As others have said, your problem may be a loose connection.