AC - Single Phase Series and Parallel

Discussion in 'Homework Help' started by RysterHD, Jun 6, 2016.

  1. RysterHD

    Thread Starter New Member

    Dec 15, 2015
    8
    0
    Okay, so i've got some questions and I seem to be struggling on part of them, mainly the phase angles, real and apparent powers,

    1.
    Here is the information i know
    Inductive reactance = 27.646 ohms
    Z = 57.134
    Current from power supply = 0.8751 A
    Vl = iXl = 24.193 V
    VR = 43.755 V

    Now the part i got wrong:
    I did the square root of 43.755^2 + 24.193^2 which = 49.998
    To work out the phase angle i did = cos^-1 (24.193/49.998) which = 61 degrees (wrong)
    Apparent power = Vsis = 50x0.8751 = 43.755 (wrong)
    Real Power = Vsis x cos(theta) = 43.755 x cos 61.06 = 21.173 (wrong)

    Any help with these would be appreciated.

    2. Here is the information i know
    Xc = 39.7887
    Z = 63.899
    i = 0.7825 A
    Vc = iXc = 31.135
    VR = 39.125

    Now the parts i got wrong :
    I tried to work out the phase angle by doing Cos ^-1 (31.135/50) = 51.488 degrees (wrong)
    Apparent power = Vsis = 50x0.7825 = 39.125 (wrong)
    Real Power = Vsis x cos(theta) = 30.125 x cos(51.488) (wrong)

    The final question:

    3.
    a)Calculate Power factor of the circuit
    b) calculate the value of capacitance needed to bring the circuit to unity power factor

    Here is the information given :
    Xl = 27.646
    Z = 57.134
    i=0.8751
    VL = 24.193
    VR = 43.755
    Apparent Power = 43.755
    Real Power = 21.173

    So here is my working:
    Square root of 43.755^2 - 21.173^2 = 38.291

    Power factor = real/apparent = 21.173/43.755 = 0.484 (wrong)
    Q = E^2/X
    X = E^2/Q = 50^2/38.291 = 65.289 ohms (wrong)
    C = 1/2 x pi (3.14159) x f x Xc = 1/2 x pi x 200 x 65.289
    C = 1.2188496x10^-5
    =12.19 uF

    Any help with these questions would be appreciated, it is good practice for me

    Thank you for your time
     
  2. DGElder

    Member

    Apr 3, 2016
    344
    85
    1.
    Since you show no schematic or provide any context I will have to guess what you are trying to do, but if I get it..
    the phase angle is = sin^-1 (24.193/49.998) = 28.9 deg.
     
  3. WBahn

    Moderator

    Mar 31, 2012
    17,737
    4,789
    It would be very handy if you would at least tell us if the circuits in question are series or parallel, instead of making us guess.

    In the first problem, assuming the components are in series (which seem like they have to be), what is the voltage across the power supply?

    If you know the voltage across the supply and the current through the supply, what is the apparent power?
     
  4. JoeJester

    AAC Fanatic!

    Apr 26, 2005
    3,373
    1,158
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