Mod, delete this...
Last edited:
AC Real Power
- Thread starter CWorthington
- Start date
Unfortunately neither your circuit nor your question make a lot of sense.
Looking at the circuit, take the voltages shown across the resistor branches.
The 41.91Ω||84.54Ω branch has an equivalent resistance of 28.02Ω.
Since this parallel branch is effectively in series with the 70.88Ω branch you would expect the ratio of their voltage drops to be 70.88/28.02 or 2.53:1.
In fact the circuit shows the voltages as 2.77/1.13 or 2.45:1. There is an obvious inconsistency for starters.
You need to have a careful look at the whole problem again and restate exactly what you do know about the circuit.
Looking at the circuit, take the voltages shown across the resistor branches.
The 41.91Ω||84.54Ω branch has an equivalent resistance of 28.02Ω.
Since this parallel branch is effectively in series with the 70.88Ω branch you would expect the ratio of their voltage drops to be 70.88/28.02 or 2.53:1.
In fact the circuit shows the voltages as 2.77/1.13 or 2.45:1. There is an obvious inconsistency for starters.
You need to have a careful look at the whole problem again and restate exactly what you do know about the circuit.
