AC power and coupling

Discussion in 'Homework Help' started by Joess7, May 19, 2009.

  1. Joess7

    Thread Starter New Member

    May 12, 2009
    3
    0
    In an AC serie network with ac voltage of 40V, serie resistor RS 200Ω, and a capacitor Xs -100Ω. i have found the load impedance ZL to be (200+J100)Ω.
    now; If this circuit was to connected to pure resistance circuitry, a/ what would be the formula to fine the RL Load resistor?. b/and what would the value of the resistor be?
    thank you
     
    Last edited: May 19, 2009
  2. R!f@@

    AAC Fanatic!

    Apr 2, 2009
    8,750
    759
    care to explain a bit more. U are not making much sense
     
  3. aliensong

    New Member

    May 13, 2009
    7
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    Hi, please explain more clearly, thanks!
     
  4. gryskop

    Member

    Mar 1, 2008
    26
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    I did j-notation so many years ago, I honestly forgot all of that, BUT, hope this link might be of some help :cool:
     
  5. Joess7

    Thread Starter New Member

    May 12, 2009
    3
    0
    I thought I have already posted this but.. I found the answer to my question..the formula for an RL ( load resistance ) in an AC network contening resistores and unductors is squareroute of RS (serie resistor) square plus XC ( capacitive reatance) square. and the value of the load resistance in this circuit is 223.6 ohms. thank you guys...
     
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