# AC power and coupling

Discussion in 'Homework Help' started by Joess7, May 19, 2009.

1. ### Joess7 Thread Starter New Member

May 12, 2009
3
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In an AC serie network with ac voltage of 40V, serie resistor RS 200Ω, and a capacitor Xs -100Ω. i have found the load impedance ZL to be (200+J100)Ω.
now; If this circuit was to connected to pure resistance circuitry, a/ what would be the formula to fine the RL Load resistor?. b/and what would the value of the resistor be?
thank you

Last edited: May 19, 2009
2. ### R!f@@ AAC Fanatic!

Apr 2, 2009
8,750
759
care to explain a bit more. U are not making much sense

3. ### aliensong New Member

May 13, 2009
7
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Hi, please explain more clearly, thanks!

4. ### gryskop Member

Mar 1, 2008
26
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I did j-notation so many years ago, I honestly forgot all of that, BUT, hope this link might be of some help

5. ### Joess7 Thread Starter New Member

May 12, 2009
3
0
I thought I have already posted this but.. I found the answer to my question..the formula for an RL ( load resistance ) in an AC network contening resistores and unductors is squareroute of RS (serie resistor) square plus XC ( capacitive reatance) square. and the value of the load resistance in this circuit is 223.6 ohms. thank you guys...