AC Inductor Help

Discussion in 'Homework Help' started by chris3spice, Sep 30, 2012.

  1. chris3spice

    Thread Starter New Member

    Aug 28, 2012
    5
    0
    Should be simple for some of you guys but I am stuck on it

    I have a simple AC Source and an Inductor all that was given me was
    Vt = 30 Vrms
    It = 15 mA
    f = 159.155 kHz

    They want me to find L and Xl but when I try to plug the numbers into the formula's I know it doesn't work out so I may be doing it wrong or something so I'd like to know how you'd find it for sure.

    I tried dividing I by V to get Xl be cause the book says I=V/Xl

    so Xl = .015/30 = .5mH

    but when I plug .5mH back in it doesn't work out 30/.0005 = 60000
     
  2. Kermit2

    AAC Fanatic!

    Feb 5, 2010
    3,789
    945
    I divided by V = 1/XI not XI

    and 1/.0005 is 2000

    30/2000 = .015
     
  3. chris3spice

    Thread Starter New Member

    Aug 28, 2012
    5
    0
    Thanks! I messed up my algebra...I feel really stupid at the moment now :p
     
  4. vk6zgo

    Active Member

    Jul 21, 2012
    677
    85
    Well for a start Xl is in Ohms not mH!

    Xl=V/I,so as you said in your last posting,Xl = 30/.015 =2000Ω!!!!

    Xl =2∏fL,where you know what 2∏ is,& f is given:

    Dividing Both Sides by 2∏f gives us L=Xl/2∏f (in Henries!)
     
    Last edited: Oct 1, 2012
  5. vk6zgo

    Active Member

    Jul 21, 2012
    677
    85
    I think a little revision of Ohm's Law may be in order!:D
     
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