Can someone show me the steps on how to tackle this?

In a series RL circuit the applied voltage is vT (t) = 10 sin(120πt + 60) Volts.
Assume that the resistance is R = 10 Ω and that the current has a phase angle of zero.

Thanks in advance. This should be a fairly easy question for you guys, but I have some difficulty.

 

easy, there is no question asked. Perhaps you want the magnitude of the current?

 

While there is math in this, this is fundamentally an electronics problem. I could have used homework or electronics chat, and chose the forum I felt it would get more help.

 

Stating the actual question might help a bit....

 

My apologies.

Find vR(t) , vL(t) and i(t).

 

My apologies.

Find vR(t) , vL(t) and i(t).

I believe all you have to do is find the total impedance of the circuit, and divide the voltage (in phasor form) by the impedance (in phasor form), to get the current. Once you find the current, i(t), since it is a series circuit, it won't change at any point. You can multiply the current (in phasor form) by the impedance of R and the impedance of L to get the corresponding voltages across the elements. Just remember Ohm's Law: V=IR.