AC Circuits - Help

Discussion in 'General Electronics Chat' started by Jay Dee, May 10, 2012.

  1. Jay Dee

    Thread Starter New Member

    May 10, 2012
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    0
    Can someone show me the steps on how to tackle this?

    In a series RL circuit the applied voltage is vT (t) = 10 sin(120πt + 60) Volts.
    Assume that the resistance is R = 10 Ω and that the current has a phase angle of zero.

    Thanks in advance. This should be a fairly easy question for you guys, but I have some difficulty.
     
  2. russ_hensel

    Well-Known Member

    Jan 11, 2009
    818
    47
    easy, there is no question asked. Perhaps you want the magnitude of the current?
     
  3. Wendy

    Moderator

    Mar 24, 2008
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    While there is math in this, this is fundamentally an electronics problem. I could have used homework or electronics chat, and chose the forum I felt it would get more help.
     
  4. DerStrom8

    Well-Known Member

    Feb 20, 2011
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    Stating the actual question might help a bit.... :D
     
  5. Jay Dee

    Thread Starter New Member

    May 10, 2012
    2
    0
    My apologies.

    Find vR(t) , vL(t) and i(t).
     
  6. DerStrom8

    Well-Known Member

    Feb 20, 2011
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    I believe all you have to do is find the total impedance of the circuit, and divide the voltage (in phasor form) by the impedance (in phasor form), to get the current. Once you find the current, i(t), since it is a series circuit, it won't change at any point. You can multiply the current (in phasor form) by the impedance of R and the impedance of L to get the corresponding voltages across the elements. Just remember Ohm's Law: V=IR.
     
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