ac 3 phase

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yoamocuy

Joined Oct 7, 2009
84
L=0.1 H
R=10Ω
C=150uF

calculate the rms value of the line current.

Here's my attempt at a solution.

L=XL/(2*pi*f)
0.1=XL/(2*pi*50)
Xl=31.4

Xc=1/(2*pi*f*C)
Xc=1/(2*pi*50*150*10^-6)
Xc=21.2

VL=sqrt(3)*VP
Vp=415/sqrt(3)
Vp=239.6 V

total impedance of one line=14.28 at an angle of 45.5°

IP=239.6/14.28
IP=16.78A at an angle of -45.5°
IP=IL

at ths point I'm not sure if IL is the same as the rms value of the current or if its different.
 

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