Hello I'm Korean student. I visited this site because I can't solve my homework.

This is synchronous counter with parallel.

My homework is changing this synchronous counter counter to upgrade version....
The homework counter works that. (The clue/hint is 'Universal Shift Register')
Load / Count
0 0 no change
0 1 up counter
1 0 set counter value
1 1 down counter

It's so hard to me... But this is my final exam question.
Although I can't speak English well, I think that you can understand my question.

plz~~~ help me!!

 

So how exactly does a universal shift register implement four different functions?
Hint, the one word answer begins with the letter 'M'

 

(The clue/hint is 'Universal Shift Register')

It works that
S1, S0 -> 0, 0 : No change
S1, So -> 0, 1 : Shigt right
S1, S0 -> 1, 0 : Shift left
S1, So -> 1, 1 : Parallel load