About CMRR?

Discussion in 'General Electronics Chat' started by rougie, Sep 18, 2013.

  1. rougie

    Thread Starter Active Member

    Dec 11, 2006
    410
    2
    Hello,

    In reference to WBahn's blog at #(33) can we express:

    Vout = Ad(Vd +/- Vcm/CMRR)

    as to express a certain margin of error just as they have done at the bottom of this link:

    http://en.wikipedia.org/wiki/Common-mode_rejection_ratio

    I know they did that for an open loop gain but I see the formulas are similar?

    thanks all for help
     
  2. rougie

    Thread Starter Active Member

    Dec 11, 2006
    410
    2
    ooooppss
    open loop gain!!!

    i get it....
    r
     
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