# A8Q3.Voltage values

Discussion in 'General Electronics Chat' started by lemon, Feb 28, 2010.

1. ### lemon Thread Starter Member

Jan 28, 2010
125
2
Hi:
I have answered the questions to a problem but am not sure I am right. Would somebody be good enough to check please.

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2. ### hgmjr Moderator

Jan 28, 2005
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Have you been directed to work in the CGS units? If so, I think you may need to convert 1.2Tesla into the equivalent value in Gauss?

hgmjr

3. ### lemon Thread Starter Member

Jan 28, 2010
125
2
No. We work in SI units. The Tesla is the correct unit for us

4. ### hgmjr Moderator

Jan 28, 2005
9,030
214
Yes. Tesla is consistent with SI units. Since SI is the stipulated units, then you need to convert the units of measure for length to meters instead of centimeters. Right?

hgmjr

5. ### lemon Thread Starter Member

Jan 28, 2010
125
2
yes. From mm to meters. I did that for the 75mm x 75mm into 0.75m^2

6. ### hgmjr Moderator

Jan 28, 2005
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1000 mm = 1 meter, then 75mm = .075 meters. Right?

hgmjr

7. ### lemon Thread Starter Member

Jan 28, 2010
125
2

why do I have the same values for E-max and E-rms?
Are the results ok now?

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8. ### hgmjr Moderator

Jan 28, 2005
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I think that the formula for the Vpeak is:

Epeak = NABf.

I believe that Faraday's Law uses frequency rather than radians in the formula.

Epeak = 3600 * 0.005625 * 1.2 * 75 = 1822.5 volts

I think it would be a good idea to get someone else in the forum to put their 0.02 worth into this discussion.

hgmjr

9. ### lemon Thread Starter Member

Jan 28, 2010
125
2
is it not BAN2∏f?

10. ### hgmjr Moderator

Jan 28, 2005
9,030
214
I did some googling and some of the sites seem to use frequency. Then I looked at other sites and they supported the 2*pi()*f factor. I would go by the information contained in your textbook just to be safe.

hgmjr

11. ### lemon Thread Starter Member

Jan 28, 2010
125
2
I'm going with you.
Which would make E-rms=1822.5/√2
=1288.702109V
or 1.3kV (2s.f.), right?

12. ### hgmjr Moderator

Jan 28, 2005
9,030
214
That is the answer I get based on frequency. What does your textbook say?

hgmjr

13. ### lemon Thread Starter Member

Jan 28, 2010
125
2
the answer is based on omega in our book. I must go with that.