My professor asked me to also find the voltage drop V2(t) across the middle section using voltage divider (it's a section consists 30ohm in parallel to the 5mF capacitor). I found V(t) across current source, but I don't get the point of using voltage divider to get V2(t). Can't I just use the current going through the middle section and use ohm's law to find V2(t)? The equation for v2 is 10angle45°(30+(-j/ωC)) but I didn't use voltage divider to find it. Could anyone explain me why I have to use voltage divider to get V2(t)? I apologize for putting "a" in the title. I couldn't post this thing because of the title so I put some random letter.