a question regarding this article

Discussion in 'Homework Help' started by transgalactic, May 17, 2008.

  1. transgalactic

    Thread Starter Active Member

    Apr 29, 2008
    74
    0
  2. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    What voltage source are you referring to?

    hgmjr
     
  3. transgalactic

    Thread Starter Active Member

    Apr 29, 2008
    74
    0
    the voltage source of the minimised
    Thevenin circuit

    ???
     
  4. hgmjr

    Moderator

    Jan 28, 2005
    9,030
    214
    If you temporarily remove the 2 Ohm resistor from the circuit, you will end up with a total voltage across R1 and R3 of 21 volts (28V - 7V). The total resistance in the loop is 5 ohms. Ohm's Law permits you to calculate the current in the loop by dividing 21 by 5. The current is 4.2 Amps. Next, mulitply 4 Ohms times 4.2 Amps and you get 16.8 volts dropped across R1. Subtract 16.8 Volts from 28 Volts and you get 11.2 Volts. This is where the 11.2 volts comes from.

    hgmjr
     
    Last edited: May 17, 2008
  5. transgalactic

    Thread Starter Active Member

    Apr 29, 2008
    74
    0
    thanks i think igot think
    ill try to apply it to other questions
     
Loading...