Forgetting maths and theory for a moment -- would it really be that much in practice?Nothing in the circuit has 50A. If you short the battery then 50A will try to heat it with (10V x 50A=) 500W!
Hmm... So I assume that if I were to add another 1ohm resistor in series (R2), the amps the 10v would be be able to deliver to that second load (R2) would decrease even further...The .2Ω is in series with the 1Ω load.
Ohms laws states that 1 volt of electrical pressure will force 1 amp of current through a 1Ω load.
So, from what I understand: figuring out the voltage at a load is on a load-by-load basis. So if I have two resistors, R1 and R2, each has a different voltage. Right?The 0.2 ohms internal resistance of the battery is in series with the 1 ohm load so the current is (10V/1.2 ohms=) 8.33A.
The 1 ohm load has a current of 8.33A so the voltage across it is (8.33A x 1 ohm=) 8.33V.
If this was directed at me as per my comment above your post, then I was merely thinking out loud in that comment. But please correct me if you see an error in my thinking/logicIf only I thought that you were genuinely looking for help I probably would answer.
maybe. if they are the exact same value, then they should drop the same voltage. if for example, R1 is 2Ω, and R1 is 1Ω, then no, they will have different drops.So, from what I understand: figuring out the voltage at a load is on a load-by-load basis. So if I have two resistors, R1 and R2, each has a different voltage. Right?
in a pure series circuit, the same amperage flows through all components. you calc this amperage by adding all the series resistances and then divide the voltage by that. for example if your R1 is 1Ω, R2 is 2Ω, and battery internal resistance is .2 ohms, then your total series resistance is 3.2Ω. if Rtot = 3.2Ω & voltage = 10V, then the amperage in all the circuit components is 3.125A.But does each load have its own amperage? or is the amperage the same throughout the circuit?
Please don't mind him. He's not a good representation of the communityIf this was directed at me as per my comment above your post, then I was merely thinking out loud in that comment. But please correct me if you see an error in my thinking/logic
true. I've not looked into the credit card sized LiPo, but I have been looking at what people are doing with the hobby "brick LiPo" (the kind used in model aircraft) and they routinely catch them on fire when precautions are not followed. Particular attention needs to be paid to the charge & discharge rates, the charge level, and the health of each individual cell. A bad cell can heat up and catch the battery on fire, and LiPo makes a relatively violent fire. Caution should be used. always charge outdoors, and it is recommended to charge inside a clay or ceramic planter pot, with a steel plate on top.400A into the 10mΩ internal resistance of the battery is 1600W!
A battery the size of a credit card will catch on fire very quickly with that much heating and how will you extinguish it? You don't.
Oh yea, it will pretty much explode into flames if you short it with a screwdriver or something. The cell has a 20C drain rating or 44A continuous. That would be the limit on what you can pull out of it. Still it can deliver max drain with a drop of less than a half volt.400A into the 10mΩ internal resistance of the battery is 1600W! A battery the size of a credit card will catch on fire very quickly with that much heating and how will you extinguish it? You don't.
by Jake Hertz
by Aaron Carman
by Aaron Carman