4QC (Full bridge) transistor duty cycle

Discussion in 'Homework Help' started by refuser, May 21, 2013.

  1. refuser

    Thread Starter New Member

    Dec 11, 2009
    I'm going through an old exam where we have a 4QC like in this image (don't mind the component values they are not correct).

    Now a part of the task is to calculate losses. The duty cycle is 80% but in the solutions they are sharing the flyback diode load equally over the diode and the transistor. So that transistor conducting percentage is 80%+0.5*20% and the flyback diode conducting percentage is 0.5*20%.

    What I dont get is how you can divide the flyback diode work over the diode and the transistor (they are IGBTs actually)?
    Last edited: May 21, 2013