4QC (Full bridge) transistor duty cycle

Discussion in 'Homework Help' started by refuser, May 21, 2013.

  1. refuser

    Thread Starter New Member

    Dec 11, 2009
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    I'm going through an old exam where we have a 4QC like in this image (don't mind the component values they are not correct).
    [​IMG]

    Now a part of the task is to calculate losses. The duty cycle is 80% but in the solutions they are sharing the flyback diode load equally over the diode and the transistor. So that transistor conducting percentage is 80%+0.5*20% and the flyback diode conducting percentage is 0.5*20%.

    What I dont get is how you can divide the flyback diode work over the diode and the transistor (they are IGBTs actually)?
     
    Last edited: May 21, 2013
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