Hi guys.
Got a question for a tutorial sheet we're doing and can't rap my head around the values I've worked out.
heres the question
A Y connected, 400V (line), 100KVA rated, stand alone generator is operating at 80kW at rated current with a lagging power factor and rated terminal voltage. The synchronous reactance is 2Ω.
Draw the per phase equivalent circuit and calculate:
(i) The Phase Current (Iph)
(ii) The Power Factor
(iii) The Reactive Power
(iv) The Voltage drop across the Synchronous Reactance (VXS)
So I've drawn the per phase equivalent circuit.
I then calculated the phase voltage by Vph = Vline / root3 to get a value of 230.9V
Iph was then found from S (apparent power) = IV rearrange to get I = 57735 (per phase power)/230.9
This gives a value of Iph as 250A which seems slightly high.
Continuing on i find power factor to be 0.8 from P = IVcostheta where costheta is the power factor.
The problem comes when I calculate part iv the voltage drop.
I used Vxs = Iph * jXs (j being imaginary number) but this gives a value of 500V which is greater than Vph.
Any help is much appreciated!
Got a question for a tutorial sheet we're doing and can't rap my head around the values I've worked out.
heres the question
A Y connected, 400V (line), 100KVA rated, stand alone generator is operating at 80kW at rated current with a lagging power factor and rated terminal voltage. The synchronous reactance is 2Ω.
Draw the per phase equivalent circuit and calculate:
(i) The Phase Current (Iph)
(ii) The Power Factor
(iii) The Reactive Power
(iv) The Voltage drop across the Synchronous Reactance (VXS)
So I've drawn the per phase equivalent circuit.
I then calculated the phase voltage by Vph = Vline / root3 to get a value of 230.9V
Iph was then found from S (apparent power) = IV rearrange to get I = 57735 (per phase power)/230.9
This gives a value of Iph as 250A which seems slightly high.
Continuing on i find power factor to be 0.8 from P = IVcostheta where costheta is the power factor.
The problem comes when I calculate part iv the voltage drop.
I used Vxs = Iph * jXs (j being imaginary number) but this gives a value of 500V which is greater than Vph.
Any help is much appreciated!