3-Bit Magnitude Comparator

Discussion in 'Homework Help' started by dav_mt, Mar 15, 2005.

  1. dav_mt

    dav_mt Thread Starter New Member

    Joined:
    Nov 14, 2004
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    Hello people,
    can any one tell me how this can be done I'm stuck on the following steps

    The question says that you have 3 bits

    A2 A1 A0 which are being compared to B2 B1 B0
    whenever A >= B output is 1
    A < B output is 0

    I began by comparing A2 with B2 using the following truth table

    A2 B2 Output Intermediate
    0 0 X 1
    0 1 0 0
    1 0 1 0
    1 1 X 1

    Im stuck on the next step. What can I do and how is this connected to the next part ?

    Thanks in advance
     
    #1
  2. beenthere

    beenthere Retired Moderator

    Joined:
    Apr 20, 2004
    15,815
    272
    Hi,

    Look up the internal logic of a 7486 (or 74HC86) magnitude comparitor and see how that works.
     
    #2
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