3-Bit Magnitude Comparator

Discussion in 'Homework Help' started by dav_mt, Mar 15, 2005.

  1. dav_mt

    dav_mt Thread Starter New Member

    Nov 14, 2004
    Hello people,
    can any one tell me how this can be done I'm stuck on the following steps

    The question says that you have 3 bits

    A2 A1 A0 which are being compared to B2 B1 B0
    whenever A >= B output is 1
    A < B output is 0

    I began by comparing A2 with B2 using the following truth table

    A2 B2 Output Intermediate
    0 0 X 1
    0 1 0 0
    1 0 1 0
    1 1 X 1

    Im stuck on the next step. What can I do and how is this connected to the next part ?

    Thanks in advance
  2. beenthere

    beenthere Retired Moderator

    Apr 20, 2004
    Missouri, USA (GMT -6)

    Look up the internal logic of a 7486 (or 74HC86) magnitude comparitor and see how that works.
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