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Old 03-15-2005, 02:22 PM
dav_mt dav_mt is offline
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Join Date: Nov 2004
Posts: 4

Hello people,
can any one tell me how this can be done I'm stuck on the following steps

The question says that you have 3 bits

A2 A1 A0 which are being compared to B2 B1 B0
whenever A >= B output is 1
A < B output is 0

I began by comparing A2 with B2 using the following truth table

A2 B2 Output Intermediate
0 0 X 1
0 1 0 0
1 0 1 0
1 1 X 1

Im stuck on the next step. What can I do and how is this connected to the next part ?

Thanks in advance
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Old 03-16-2005, 12:59 AM
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beenthere beenthere is offline
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Join Date: Apr 2004
Location: Missouri, USA (GMT -6)
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Look up the internal logic of a 7486 (or 74HC86) magnitude comparitor and see how that works.
First comes the hardware, then the software.
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