De Morgan's theorem

Hello, this is my first post.
Sorry if I did any mistake.

In this page http://www.allaboutcircuits.com/vol_4/chpt_8/3.html
It says "Show that (A'+B') = AB"
It's not true. And after the image that it follows, the text explains, so I could figure out if the quote was supposed to be (A'+B')=(AB)' or (A'+B')'=(AB) and it's the second option.

I hope I've helped.

You did good. Is this the section you are having problem with?

Example:


Show that (A'+B') = AB


Solution: below figure, lower left

Click to expand...

It is quite late for me and I'm too tired to get into it deeply. If this is the problem area let us know.

It looks like an error.

From the following paragraph, it seems it should be

(A'+B')'=AB

Click to expand...

as this is what is proven in the graphics and textual explanation following.

Bill_Marsden said:

You did good. Is this the section you are having problem with?



It is quite late for me and I'm too tired to get into it deeply. If this is the problem area let us know.

Click to expand...

Yeah, this is the section.
*feeling good about having been able to help*

I don't know if you want a hand with the fix...
I could help.

tshuck said:

It looks like an error.

From the following paragraph, it seems it should be as this is what is proven in the graphics and textual explanation following.

Click to expand...

I agree that this is the best fix. No point in re-drawing the graphic.

Georacer said:

I agree that this is the best fix. No point in re-drawing the graphic.

Click to expand...

Thanks kiroma and all for figuring this one out.

I have entered the proposed change at ibiblio.org

Dennis Crunkilton