I'm trying to simplify this expression.
a'b'c'+a'bc'+a'bc+ab'c+abc'+abc
so far I have
(a'b'c'+abc)+ (a'bc'+abc)+(a'bc+abc)+ (ab'c+abc)+ (abc'+abc)
b(a'+a)(c'+c) + bc(a'+a) + ac(b'+b) + ab(c'+c)
b + bc + ac + ab
I'm stuck here and the final solution is 3 terms with 5 literals.
Thank you for your help.
a'b'c'+a'bc'+a'bc+ab'c+abc'+abc
so far I have
(a'b'c'+abc)+ (a'bc'+abc)+(a'bc+abc)+ (ab'c+abc)+ (abc'+abc)
b(a'+a)(c'+c) + bc(a'+a) + ac(b'+b) + ab(c'+c)
b + bc + ac + ab
I'm stuck here and the final solution is 3 terms with 5 literals.
Thank you for your help.