hi guys,
i have this problem which seems very easy as it only uses basic kvl and kcl.
but the answer im getting to is different from the one in the book.
plus both of the answers (the book's and mine) seems to not settle with kcl and kvl in other junctions and loop which makes me think that there is a mistake in the problem itself.
the goals are to find the currents Ix and Ie2 (both of them are marked in the right side of the circuit).
there is also another question that asks if the power output of the two current sources will change if the points a and b will be connected with a short circuit (just wire no resistance). the answer says that only Is2 (the source just under the points) will change its power because it will have a different voltage drop on it. that doesnt makes sense to me because of kvl in that loop - connecting a wire between a and b will not change the voltage source next to the points so kvl in that loop will remain the same.
please help me understand this problem
thank you!
ps:
if its not clear - the dependant current source (Is2) is αIx (and not α minus Ix).
EDIT: on the resistor R2 the voltage drop is 17.5v (i just noticed that the point is not seen)
i have this problem which seems very easy as it only uses basic kvl and kcl.
but the answer im getting to is different from the one in the book.
plus both of the answers (the book's and mine) seems to not settle with kcl and kvl in other junctions and loop which makes me think that there is a mistake in the problem itself.
the goals are to find the currents Ix and Ie2 (both of them are marked in the right side of the circuit).
there is also another question that asks if the power output of the two current sources will change if the points a and b will be connected with a short circuit (just wire no resistance). the answer says that only Is2 (the source just under the points) will change its power because it will have a different voltage drop on it. that doesnt makes sense to me because of kvl in that loop - connecting a wire between a and b will not change the voltage source next to the points so kvl in that loop will remain the same.
please help me understand this problem
thank you!
ps:
if its not clear - the dependant current source (Is2) is αIx (and not α minus Ix).
EDIT: on the resistor R2 the voltage drop is 17.5v (i just noticed that the point is not seen)
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