I'm a little confused about something power related. I'm sure this is all very fundamental so please take it easy on me. I believe I understand how transformers work (induction from one coil to another where a current exists through the primary and a load is put on the secondary) and the basic 3 phase (120 degrees out of phase with each other) system, and the sqrt 3*VAC source gives the per phase voltage (~277 per phase if Vs is 480). The thing I'm confused about is how a hot line can be considered a neutral after exiting the secondary of a transformer.
I'll elaborate: imagine a 3 phase 440VAC system comprised of L1, L2, L3 and GND... L1, L2, and L3 go off in one direction and in another direction L2 and L3 enter the primary of a step down transformer with a 115VAC (or 117VAC) secondary. So on each side of the primary winding you have a line (L2 and L3). The thing I'm confused about is how one of the sides of the secondary winding can be treated as a neutral. How do you go from a hot to a neutral through a transformer? I'm obviously missing something (probably something simple). The transformer in question is a 2TX 500 VA transformer. If someone can show me the math there going from 440 to 115 it'd be a welcomed review. Is it simply 440/2 = primary side = 220, 220/sqrt 3 = 127 secondary? 127 is fairly close to 115 or 117... Perhaps the ~10V difference can be attributed to I^2*R losses... What am I missing? Also what is to stop the ac secondary L2 and L3 from oscillating in the same (or opposite) fashion as the primary? The components connected to the single phase side are connected such that one of the secondary lines of the transformer is connected to the neutral pins.
Any explanations you can provide would be appreciated. Thanks!
I'll elaborate: imagine a 3 phase 440VAC system comprised of L1, L2, L3 and GND... L1, L2, and L3 go off in one direction and in another direction L2 and L3 enter the primary of a step down transformer with a 115VAC (or 117VAC) secondary. So on each side of the primary winding you have a line (L2 and L3). The thing I'm confused about is how one of the sides of the secondary winding can be treated as a neutral. How do you go from a hot to a neutral through a transformer? I'm obviously missing something (probably something simple). The transformer in question is a 2TX 500 VA transformer. If someone can show me the math there going from 440 to 115 it'd be a welcomed review. Is it simply 440/2 = primary side = 220, 220/sqrt 3 = 127 secondary? 127 is fairly close to 115 or 117... Perhaps the ~10V difference can be attributed to I^2*R losses... What am I missing? Also what is to stop the ac secondary L2 and L3 from oscillating in the same (or opposite) fashion as the primary? The components connected to the single phase side are connected such that one of the secondary lines of the transformer is connected to the neutral pins.
Any explanations you can provide would be appreciated. Thanks!