Please don't upload .doc or .docx formats. If a simple .png image isn't enough, use the .pdf at least.
Many members are reluctant to use the .doc format.
.I am a prisoner of high standards and low social skills
I wish I was the best at what I would do, and what I would do wouldn't be pretty.
Personally I think the solution to part (c) is overcomplicated.
Since it is required to find Vo/Vs, I would simply assume a voltage source of value Vs is applied to the emitter.
From there one can observe that
Given that, one can then determine the output as a function of vs since
or Av=6.744 [which seems a better estimate to me than 6.73]
|analysis, bjt, problem|
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