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#1
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Hey guys.
I have the following example in my notes but there is no working. Could someone please explain how to reach to solution? Is he acutely using integration or is he just looking at the "sift property" and noting values of t0, t1, t2 to come to a conclusion. Here is the question ![]() The Solution ![]() Sifting property noted earlier in my notes ![]() thanks a lot guys
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Give me a lever long enough and a fulcrum on which to place it, and I shall move the world. -Archimedes |
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#2
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It's shifting property, not sifting property. If it was sifting, you'd use it in the kitchen with flour.
![]() The solution is staring you in the face. One way to think of the delta function is that it is a continuous analog of the Kronecker delta. It is often used to evaluate an expression at a particular point. Thus, in the example, the function x is evaluated at t = 4. Here's the analogy. For a discrete sum using the Kronecker delta (and I'm using the Einstein summation convention), The continuous analog is Assume the integration is over the real line. |
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#3
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#4
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Quote:
Oh, another explanation is that I missed that day in class.
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#5
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Hehehe
Was that when frequency was spec'd in CPS instead of HZ?
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www.xilinx.com |
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#6
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good stuff.
Yeah I was wondering what was going on there. My lecture notes said "Sifting" like 20 times haha. cheers guys
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Give me a lever long enough and a fulcrum on which to place it, and I shall move the world. -Archimedes |
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| Tags |
| evaluating, impulse, integral, signal, unit |
Related Site Pages
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| Section | Title | |||
| Worksheet | Linear computational circuitry | |||
| Textbook | Computational circuits : Practical Analog Semiconductor Circuits | |||
| Video Lecture | Asynchronous Counters - Digital | |||
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