Boolean Algebra Help

Hey guys, Im struggling getting my head around this Boolean algebra stuff

Im stuck on where to start with what seems to be a simple problem:

f=(ab).c+d There is a bar over each variable plus a bar over the whole equation.

Any help is greatly appreciated
Thanks

42.

If you don't tell us where you're trying to go, any road will get you there...

I assume you want to simplify the expression -- but your notation is a bit strange. Is "ab" a single symbol or does it signify multiplication? I assume the period means multiplication. I'll assume the overbars denote negation, so look up De Morgan's Laws for some help to get started.

sorry about that, yes i need to simplify it so that the final expression is a Sum of Product expression with no bar appearing in the expression. I'll keep looking into it, the textbook been used brushes over the topic with only 1 example which seems to be much easier. sooo frustrating

someonesdad said:

42.

Click to expand...

Mostly Harmless

lol. So i watched some videos i found on youtube and had a attempt,

I'll represent the bar with ' and double bar is ''

so f=(ab)' *c'+d' with a bar over the whole thing
-- =(ab)''+c''+d''
=(a''+b'')+c''+d'' since a''=a
=(a+b)+c+d

What do you think??

cant figure out how to enter it correctly into the calculator, i want to see it on paper too so i can see the process

Joepiper5 said:

cant figure out how to enter it correctly into the calculator, i want to see it on paper too so i can see the process

Click to expand...

Hello, you made a small mistake in your first step:

= (ab)''+c''+d''

Click to expand...

When you break apart the top-most negation bar the + d' becomes * d'', like this:

= [(ab)''+c'']*d''

(Note the brackets to maintain the correct grouping of d'' with the remaining expression).

Also, in step 2: (ab)" = (ab), instead of (a"+b"). You can treat everything in the parentheses as a unit, so negating the negation just gives you back the original expression.

See if you can work it through again.
^Mike^

Thank you so much mike. I appreciate the help