Under the volume II AC section of the e-book their is a chapter devoted to the electric pendulum which is an LC circuit that is exposed to a DC source then cut off. I am confused about this sentence.
"If either the capacitor or inductor starts out in a charged state, the two components will exchange energy between them, back and forth, creating their own AC voltage and current cycles."
I did some rough calculations on paper and it didn't make sense to me. When the LC circuit gets exposed a DC voltage the capacitor should have the same voltage drop as the source and no current going through it eventually. While the inductor should have zero voltage drop across it and all the current going through it eventually. I am making these conclusions based on the fact that the circuit is in steady state with DC voltage applied to it. Well when the DC voltage is popped off we are left with just an inductor and capacitor in series now. So if an inductor resists changes in current shouldn't the instantaneous current going through the inductor stay at its max current when the DC voltage is cut off? The example says the current going through the inductor is at 0 when it starts oscillating.
So my question is in order for their to be oscillation in a tank circuit should only one component (L or C) be charged in order for oscillation to occur? And if both are charged then oscillation can't happen?
Thanks in advance!
"If either the capacitor or inductor starts out in a charged state, the two components will exchange energy between them, back and forth, creating their own AC voltage and current cycles."
I did some rough calculations on paper and it didn't make sense to me. When the LC circuit gets exposed a DC voltage the capacitor should have the same voltage drop as the source and no current going through it eventually. While the inductor should have zero voltage drop across it and all the current going through it eventually. I am making these conclusions based on the fact that the circuit is in steady state with DC voltage applied to it. Well when the DC voltage is popped off we are left with just an inductor and capacitor in series now. So if an inductor resists changes in current shouldn't the instantaneous current going through the inductor stay at its max current when the DC voltage is cut off? The example says the current going through the inductor is at 0 when it starts oscillating.
So my question is in order for their to be oscillation in a tank circuit should only one component (L or C) be charged in order for oscillation to occur? And if both are charged then oscillation can't happen?
Thanks in advance!