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#1
09-26-2004, 07:26 PM
 ramesh_ime New Member Join Date: Sep 2004 Posts: 3

Can anybody help me to solve this...............??????

A one-bit full adder is to be implemented using 8-to-1 multiplexers

(a) Write the t ruth table for sum (S) and carry to the next stage CN in terms of
the two bit (A, B) and carry from the previous stage (CP) . The t ruth table
should be in the ascending order of (A,B,CP).

(B) Implement S and CN using 8-to- 1 multiplexer.

Thanks & best regards,
Ramesh Raju

 Tags 8to, multiplexer

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