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#1




discrete math sequence question
I need to come up with a rule or a formula for the following:
1,2,2,2,3,3,3,3,3,5,5,5,5,5,5,5..... 
#2




Hint: 2*n + 1 and primes

#3




There may be more than one pattern that gives that initial sequence. One solution is: the digits 1,2,3,and 5 are primes (positive). The repeat frequencies seem to follow just the odd numbers. The next three repeat frequencies would be 9, 11 and 13. That is, the next two sequences would be nine 7's, then eleven 11's.
John 
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s3b4k (03112010) 
#4




ok thanks a lot for the help, but is there an exact formula i can use, or is it only solvable by explaining it?

#6





#7




I searched for the sequence on google and found this. Still no idea what it is.
Quote:

#8




For (b) the sequence starts with 1, and if there are at least 2 previous term, then the subsequent term is the sum of the previous two terms, otherwise it is 2 (or alternatively, the previous term is doubled). The replicates of each term is as in the first problem.
I am too tired to look at (a) now. Perhaps this question should have its own thread. John Edit: For (a) here's a reference: http://mathworld.wolfram.com/NearSquarePrime.html Last edited by jpanhalt; 03112010 at 05:24 PM. Reason: added reference 
#9




this question is driving me nuts, are the next three terms going to be 8,8,8 or 7,7,7. because it good either be prime numbers or just the sum of the previous numbers, but if its the sum of the previous numbers how do you get the two there

#10




Quote:
John PS, when I went to school 1 was still prime. But then, it was a public school. 
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s3b4k (03112010) 
Tags 
discrete, math, question, sequence 
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