Hi guys ,
All articles and lessons say " when connecting an inductor with a dc source, the first value on the inductor will be almost the same as the dc source value, then dropes gradually". How, we know that the induced voltage equals to the value of L multiplied by di/dt, so they should say that the value on the inductor at the first point, will be L di/dt, not " almost the source value".
If we consider the induced voltage to be almost the same as the source value, so any inductor with any value of L will produce the same value of Vind at the first moment!!!!!!
I think we can produced higher values of the induced voltage ( also may be higher than the source itself) if the number of turns were high enough.
I also read the lesson " Inductors and calculus ", the instructor considered a virtual experiement by connecting a neon lamp in parallel with the inductor, he said ' after closing the switch , the voltage on the coil will be the same as the source, where the source was 6 volts, so the neon lamp will not be lite, but after opening the switch (note that the inductor has very big number of turns) the neon lamp will be lite, why not at the begining?
plz give me more explaination, thanks alot
All articles and lessons say " when connecting an inductor with a dc source, the first value on the inductor will be almost the same as the dc source value, then dropes gradually". How, we know that the induced voltage equals to the value of L multiplied by di/dt, so they should say that the value on the inductor at the first point, will be L di/dt, not " almost the source value".
If we consider the induced voltage to be almost the same as the source value, so any inductor with any value of L will produce the same value of Vind at the first moment!!!!!!
I think we can produced higher values of the induced voltage ( also may be higher than the source itself) if the number of turns were high enough.
I also read the lesson " Inductors and calculus ", the instructor considered a virtual experiement by connecting a neon lamp in parallel with the inductor, he said ' after closing the switch , the voltage on the coil will be the same as the source, where the source was 6 volts, so the neon lamp will not be lite, but after opening the switch (note that the inductor has very big number of turns) the neon lamp will be lite, why not at the begining?
plz give me more explaination, thanks alot