Boolean Algebra

Boolean Algebra

a) Develop the Boolean expression for the circuit below.
b) Simplify the Boolean expression.
c) Draw a simpler circuit for the equation in b).

Thanks

We can't really show you the answer. Remember the operators of the and, nand, nor, and the inverter. Just apply those to the equation and then that's the output equation. Remember that double bars cancel.

F=[(AB'C)'+B]'' * B *(A+C')'
=[(AB'C)'+B]* B *(A+C')'
=(A'+B+C'+B) * A'BC
=A'A'BC + A'BBC + A'BCC' + A'BBC
=A'BC + A'BC + A'BC
=A'BC


This is the answer for b, do the rest on your own.