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Old 06-08-2008, 02:24 PM
monkeyhead monkeyhead is offline
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Join Date: Mar 2007
Posts: 45
Default Dc short shunt compound generator problem

I'm running through an example and trying to find out what the losses would be in the shunt field.

See attached image for the circuit diagram.

Anyhow I've figured out the following:
IL = 32 A

Vf = 259.6 V

If = 2.6 A

Ia = 34.6 A

E= 276.9V

The efficiency to be : 76.92 %

The iron,friction and windage losses to be : 819.26 W

What I'm a bit confused about is that I've found that the loss in the shunt field is equal to If * V which gives me 650 W.

However in my another notes it says that the loss in the shunt is equal to If^2 * Rf which gives me 676 W.

However which one would resemble the losses in the shunt field? Or have I gone completely the wrong way about this?

Many thanks,

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Old 07-10-2008, 03:40 AM
ahrjay007 ahrjay007 is offline
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Join Date: Jul 2008
Posts: 3

what is the answer to that Q?....
can you supply its answer?
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