I guess 2.3 is a dc voltage, am i correct?If you have a load that is "on" for 20 uS, off for 3.5 mS, which is 2.3 volts when on, zero volts off, 10mA on and zero volts off, and the current and voltage are in phase, how many watts is the load?
Thanks again, Rich
It's a square wave, so: [(amplitude)^2]^1/2 = amplitude. That is, the RMS of a square wave is the amplitude. JohnSo I don't need to use RMS?
The power, which is Joules/sec when on is 2.3*10mA = 23mW.If you have a load that is "on" for 20 uS, off for 3.5 mS, which is 2.3 volts when on, zero volts off, 10mA on and zero volts off, and the current and voltage are in phase, how many watts is the load?
Thanks again, Rich
How do I arrive at "10020us"?The power, which is Joules/sec when on is 2.3*10mA = 23mW.
So the energy when on is 23mW*20us = 460nJ
The energy when off is 0nJ.
The average power for the load is the total Joules divided by the total time.
460nJ / 10020us = 45.9e-6W or about 46uW.
I thought the RMS voltage of a rectangular wave was:It's a square wave, so: [(amplitude)^2]^1/2 = amplitude. That is, the RMS of a square wave is the amplitude. John
Sorry, I screwed that up.How do I arrive at "10020us"?