Hey guys, I have the misfortune of having a TERRIBLE AC circuits lecuturer and he cant even tell me how to calculate the Q factor for a parallel resonant circuit. He told me that the formula to do this is: R(C/L) but what i want to know is how do you take into account all the resistances. Say for example, in my Lab experiment we had a parallel resonant circuit with 1kohm resistor in one lane, a capacitor in another and an inductor in the last lane. Each component also had a series 10 ohm resistor so the voltages and phases could be read with an oscilloscope. How do i calculate the Q factor of this circuit?
Q factor for a parallel resonant circuit
- Thread starter mentaaal
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The correct formula for the Q factor is Q=R*(sqrt(C/L))
Now, the general formula for the Q factor is Q=(reactive power/average power)
the average power is the average power dissipated on the resistors
and the reactive power is the power stored by the capacitor or the inductor
Thanks for the reply, sorry about at i forgot to stick int the sqrt into the formula. Ok that makes sense but how do i calculate the q factor by the formula alone? What does R signify in this istance and how do all the other series resistors get taken into account in this formula?
