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#1
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I have read the other thread and and get rule for converting SOP to POS and that is DeMorgan and Involution. Also get example . From that example i try to convert expression from SOP to POS. So plzzz check is this true?
Given Expression A+A'B+A'C' Solution (A)(A'+B)(A'+C') Is this right? n If it is wrong plzz given me proper suggetion |
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#2
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i think
A+A'B+A'C' = A'(A'+B)'(A'+C')' = A'(A.B')(A.C) = B'C =(B+C') = 1(B+C') = (A+A')(B+C') |
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#3
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i think the following might work
A+A'B+A'C' A+A'(B+C') A+A'(B+1-C) //C+C'=1 A+A'(1-C) //1+B=1 A+A'C' (A+A')(A+C') //X+YZ=(X+Y)(X+Z) 1(A+C') A+C' |
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#4
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@CSharpque
Can you link to the other thread? I find the easiest way to be going back to the truth table and re-working it for the maxterm solution. Check this out: https://wiki.engr.illinois.edu/downl...=1251869280000
__________________
. I am a prisoner of high standards and low social skills____________________________________ I wish I was the best at what I would do, and what I would do wouldn't be pretty. |
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#5
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Plzz give me ans surely
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| Tags |
| convert, expression, pos, sop |
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