I am taking the initiative to teach myself about common emitter amplifiers.
I find hyperphysics to have a practical example of a common emitter circuit.
link provided for common emitter circuit.
http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/npnce.html#c2
So far by reviewing hyperphysics common emitter circuit example I learned that.
1) transistor has to remain in active mode in order to be used as common emitter amplifier
2) Using the transistor load line chart (Ic vs.Vce) of a 2N2222 you can determine the operating point that will keep the transistor in active mode. Ic = 4.5ma and Vce = 9V. (see transistor load line attachment)
I soon get lost in the example when I am told tha Ic max = 9 ma. 9 ma is used to derive Rc and Re (see screen shot common emitter gain)
My question is how did they get 9 ma?
Is 9 ma max Ic the maximum amount of current that the collector can withstand before turning from reversed biased (Vc > Vb) to forward biased (Vb > Vc)?
I find hyperphysics to have a practical example of a common emitter circuit.
link provided for common emitter circuit.
http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/npnce.html#c2
So far by reviewing hyperphysics common emitter circuit example I learned that.
1) transistor has to remain in active mode in order to be used as common emitter amplifier
2) Using the transistor load line chart (Ic vs.Vce) of a 2N2222 you can determine the operating point that will keep the transistor in active mode. Ic = 4.5ma and Vce = 9V. (see transistor load line attachment)
I soon get lost in the example when I am told tha Ic max = 9 ma. 9 ma is used to derive Rc and Re (see screen shot common emitter gain)
My question is how did they get 9 ma?
Is 9 ma max Ic the maximum amount of current that the collector can withstand before turning from reversed biased (Vc > Vb) to forward biased (Vb > Vc)?
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