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#1
09-27-2010, 07:37 AM
 sadaf Junior Member Join Date: Aug 2010 Location: PAKISTAN Posts: 25
current divider rule

my question is:
in cdr formula why don't we put the resistance in the numerator of that resistor across which we want to find out the current...

Ia= (Rt*It)/(Ra)

or in the special case of CDR

Ia= (Rb*It)/(Ra+Rb)

according to me, as current is inversely related with resistance so that's why.....................

#2
09-27-2010, 11:28 AM
 t_n_k Senior Member Join Date: Mar 2009 Posts: 4,964

Quote:
 my question is: in cdr formula why don't we put the resistance in the numerator of that resistor across which we want to find out the current... Ia= (Rt*It)/(Ra)
If you mean Rt=Ra+Rb then clearly you'll get the wrong result. Ia would exceed It - which would be unexpected to say the least!

Your question isn't clear to me. What is the heart of the problem from your perspective?
#3
09-28-2010, 02:07 AM
 Ghar Senior Member Join Date: Mar 2010 Location: Toronto Canada Posts: 655

Current is inversely related with resistance yes, but with current division you have two (or more) resistors in parallel rather than two (or more) resistors in series.

The branch with 0 resistance would get 100% of the current.
With a voltage divider if one resistance is 0 that resistance gets 0% of the voltage.

It's an inverted situation, you swapped voltage and current as well as series and parallel.
#4
10-06-2010, 05:07 PM
 sadaf Junior Member Join Date: Aug 2010 Location: PAKISTAN Posts: 25

OK i understood......

 Tags current, divider, rule

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