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Sparky49 Sparky49 is offline

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About Me

  • About Sparky49
    Electronics, Bagpipes, Fishing
    GCSE in Electronics
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    "Has anyone really been far even as decided to use even go want to do look more like?"


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  • Last Activity: Yesterday 06:33 PM
  • Join Date: 07-16-2011
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Latest Blog Entry

Posted 03-31-2014 at 03:32 PM by Sparky49 Comments 0
Posted in Uncategorized
Okay a little rant....

We have a design exercise to do in uni - it is a PIC based counting circuit, which counts the number of objects passing between a light source and an LDR on a conveyor belt. We were told that there should be a circuit built from op amps to convert the analogue signal from the LDR to a digital one, so the PIC could count without using any ADC kind of stuff.

Anyway.... The group I was in started off well. We sat down, decided on the number of input/output...

Posted 02-19-2014 at 10:35 PM by Sparky49 Comments 0
Posted in Uncategorized
I've been at uni for more than five months now.

Not once have I seen a soldering iron.

I've used a breadboard twice though.

This is engineering, not theoretical electron management. :P

Posted 02-11-2014 at 04:24 AM by Sparky49 Comments 0
Posted in Uncategorized
So, here's the thing.

Got coursework due in on Friday.

Lots of work set, really too much set to do during the time allotted each week (seriously, not typical student excuse).

So here I am. Not too much to do now. Mainly organising it. What good is a tidy logbook? Logbooks should be messy and filled with nuggets of information. So I need to take a picture of the LDR potential divider to prove I built it. -_- urgh. Ah well.

Also, all our...

Posted 01-06-2014 at 08:54 PM by Sparky49 Comments 0
Posted in Uncategorized

Posted 12-20-2012 at 09:50 PM by Sparky49 Comments 0
Here's the first set, chaps.

Please read the introduction post.


For the figure shown in figure 1.10, with Vin=30V and R1=R2=10k, find (a) the output voltage with no load attached (the ope-circuit voltage); (b) the output voltage with a 10k load (treat as a voltage divider, with R2 and R1 combined into a single resistor); (c) the Thevenin equivalent circuit; (d) the same as in part b, but using the Thevenin equivalent circuit; (e) the
Recent Comments
Since you are in the...
Posted 06-29-2012 at 07:20 PM by Georacer Georacer is offline
Hi everyone, the next...
Posted 06-27-2012 at 03:06 PM by Sparky49 Sparky49 is offline
Extensive recounting...
Posted 06-27-2012 at 10:10 AM by Georacer Georacer is offline

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