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Quick exercise in, design of a , Volt.PK. Detector

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Posted 10-07-2009 at 01:32 AM by hobbyist
Updated 10-07-2009 at 10:11 PM by hobbyist

Design:
Voltage Peak detector

1. Vcc = 12v.

2. Choose VCQ1 output, = 9v.

3. Choose VBQ1 = 8v.

4. VEQ1 = 7.3v.

5. choose RCQ1 = 470 ohms. (to drive a LED output)

6. IRCQ1 = (Vcc - VCQ1) / RCQ1 = ~ 6.38 mA.

7. RE is a split resistance, between the emitter of Q1 and Q2.
RE = ( REQ1 + REQ2) = (VEQ1 / IRCQ1) = ~ 1143 ohms.
So make REQ1 = REQ2 = 560 ohms each.

8. Now VEQ2 = ~ 3.65v.

9. Now with around 1100 ohms for RE, then make RB1Q1 around 2 times RE =~ 2K ohms.

10 IRB1Q1 = (VBQ1 / RB1Q1) = 4mA.

11. RB2Q1 = (Vcc - VBQ1) / IRB1Q1 = 1K ohms.

By varying the resistor value of REQ2, to a higher value, will increase VEQ2, which in turn will then detect a higher PK input voltage.

This will also raise the idle (standing voltage) at the output too.

Idle output voltage.
Input @ 4v.
No trigger of circuit.