View Full Version : Matrix solving
switchfoot
01-13-2006, 03:54 AM
Hi,
Can anyone solve this equation for G?
2(H^T) - (G^T) (H^T) H - G (H^T) H + 2 sigma^2 G =0
where H and G are square matrices,
sigma is a scalar and
T means transpose
Cheers. :)
MEGA_AMPERE
01-15-2006, 12:45 AM
naaa
can't read it right
what is this means ^
lex_ph
01-23-2006, 06:54 AM
I think that "^" thing represents "raised to". I that case H raised to T and so on.
CoulombMagician
01-23-2006, 07:23 AM
T means transpose, flip the matrix around it's diagonal so that the i,j and j,i elements are interchanged.
A matrix M for which m(i,j) = m(j,i) is said to be symmetric and M^T = M
if m(i,j) = -m(j,i) it is called antisymmetric and M^T = -M
Any square matrix G can be written as the sum of a symmetric and an antisymmetric matrix G = Gs + Ga just define Gs = (1/2)*(G + G^T)
and Ga = (1/2)(G - G^T).
Obviously ((A^T)^T) = A
Another property is (AB)^T = (B^T)(A^T) so (A^T)A = A(A^T).
If A,B are symmetric then (AB)^T = BA
I'm still trying to crack this nut 5 minutes at a time.
The Skeptic
01-27-2006, 03:33 PM
Originally posted by switchfoot@Jan 13 2006, 02:54 AM
Hi,
Can anyone solve this equation for G?
2(H^T) - (G^T) (H^T) H - G (H^T) H + 2 sigma^2 G =0
where H and G are square matrices,
sigma is a scalar and
T means transpose
Cheers. :)
Quoted post
Are you sure nothing else is known about G or H, such s their being symmetrical or something else? Here is the beggining of it. Please forget the last line, I couldn't erase it.
vBulletin® v3.8.5, Copyright ©2000-2010, Jelsoft Enterprises Ltd.